10.3.2 iOS jailbreak is possible on iPhone si iPad thanks to a vulnerability that seems to have been discovered in this version of the operating system. The vulnerability for iOS 10.3.2 that can be turned into a jailbreak solution has the code name CVE-2017-7047 and in iOS 10.3.3 it seems to have been blocked, so that only the previous version of the operating system could still be exploited now.
iOS 10.3.2 jailbreak is possible thanks to an exploit by a computer security researcher, the exploit being unstable for now, but with the potential to transform into a stable solution. Even so, the mere existence of an exploit that can be turned into an iOS 10.3.2 jailbreak solution is very good news for iPhone and iPad users who are still running this version of iOS.
iOS 10.3.2 jailbreak is expected by a lot of people, but even if a well-known hacker stated that exploitation is possible, you should not consider everything as safe. From the simple statement that iOS 10.3.2 jailbreak is possible to the release of a usable solution is a long way, so the hacker's recommendation is that users who have installed iOS 10.3.3 or iOS 11 should go back to iOS 10.3.2 now.
iOS 10.3.2 jailbreak can only be done if you do iOS beforehand 10.3.2 downgrading on iPhone or iPad, and if you want to jailbreak, I recommend that you do it right now and wait. There's no telling how long you might have to wait for an iOS 10.3.2 jailbreak solution, so you'll have to be very patient, but there's a chance that the iPhone and iPad will have something like this available at some point in the future.
If you're at #iOS 10.3.3, downgrade to 10.3.2 while you can: Ian Beer's awesome CVE-2017-7047 bit unstable, can be adapted to a dev #jailbreak
— J says: AAPL, stop changing XNU structs each beta! (@Morpheus______) August 2
